JEE Advanced Chemistry: Thermodynamics Practice Questions

12 questions with answers and step-by-step solutions. Tap any question to see the full worked solution.

  1. Q1.
    For a spontaneous process at constant temperature and pressure, which of the following conditions must be satisfied?
    Easy
  2. Q2.
    The standard enthalpy of formation of an element in its most stable state at 298 Kelvin is:
    Easy
  3. Q3.
    Which of the following statements is true for an ideal gas undergoing an isothermal reversible expansion?
    Easy
  4. Q4.
    What is the change in internal energy for an adiabatic process where work done on the system is 50 Joules?
    Easy
  5. Q5.
    For a gaseous reaction, the change in internal energy is -10 kJ at 300 Kelvin. If the change in the number of moles of gas is -2, calculate the change in enthal
    Medium
  6. Q6.
    The standard enthalpy of combustion of graphite and diamond are -393.5 kJ per mole and -395.4 kJ per mole respectively. Calculate the enthalpy change for the co
    Medium
  7. Q7.
    The entropy change for the fusion of 1 mole of a solid at its melting point of 273 Kelvin is 22 J per Kelvin. What is the enthalpy of fusion?
    Medium
  8. Q8.
    Calculate the work done when 2 moles of an ideal gas expand isothermally and reversibly from 1 liter to 10 liters at 300 Kelvin.
    Medium
  9. Q9.
    The standard Gibbs free energy change for the reaction Agoes to B is -10 kJ/mol at 300 K. If the reaction is carried out in a vessel where the partial pressure
    Hard
  10. Q10.
    For a reversible adiabatic expansion of an ideal gas with heat capacity ratio gamma, the relationship between temperature and volume is given by T times V raise
    Hard
  11. Q11.
    For a reaction at equilibrium, the temperature dependence of the equilibrium constant K is given by the van't Hoff equation. If the enthalpy of reaction is cons
    Hard
  12. Q12.
    Calculate the change in internal energy when 2 moles of an ideal gas are heated from 300 K to 400 K at constant pressure. Given Cv = 20 J/mol K.
    Hard

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