A message signal of frequency 10 kHz and peak voltage of 10 V is used to modulate a carrier wave of frequency 1 MHz and peak voltage of 20 V. Determine the modulation index.

B. 0.5 — The modulation index is defined as the ratio of the amplitude of the message signal to the amplitude of the carrier wave. Using the formula mu = Am / Ac, we get 10 / 20 = 0.5.

JEE Advanced · PhysicsMedium

$A message signal of frequency f_{m} = 10 kHz and peak voltage A_{m} = 10 V is used to modulate a carrier wave of frequency f_{c} = 1 MHz and peak voltage A_{c} = 20 V . Determine the modulation index μ .$

A. $0.25$
B. $0.5$
C. $0.75$
D. $1.0$

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Correct answer: B — $0.5$

Solution

The modulation index is defined as μ = \frac{A _{m}}{A _{c}} . Substituting the given values, μ = \frac{10}{20} = 0.5 .

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A message signal of frequency fm​=10 kHz and peak voltage Am​=10 V is used to modulate a carrier wave of frequency fc​=1 MHz and peak voltage Ac​=20 V. Determine the modulation index μ.

Solution

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More Communication Systems practice questions

$A message signal of frequency f_{m} = 10 kHz and peak voltage A_{m} = 10 V is used to modulate a carrier wave of frequency f_{c} = 1 MHz and peak voltage A_{c} = 20 V . Determine the modulation index μ .$