In a potentiometer experiment, the balancing length for a cell of EMF 1.5 volts is 300 cm. If the cell is replaced by another cell of EMF 2.5 volts, what will be the new balancing length?

B. 500 , cm — In a potentiometer, the EMF of the cell is directly proportional to the balancing length. Using the ratio of EMFs to lengths, we can solve for the unknown balancing length.

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$In a potentiometer experiment, the balancing length for a cell of EMF ε_{1} = 1.5 V is l_{1} = 300 cm . If the cell is replaced by another cell of EMF ε_{2} = 2.5 V, what will be the new balancing length l_{2} ?$

A. $400 cm$
B. $500 cm$
C. $600 cm$
D. $450 cm$

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Correct answer: B — $500 cm$

Solution

Using ε_{1} / l_{1} = ε_{2} / l_{2}, we get 1.5/300 = 2.5/ l_{2} . Solving for l_{2} gives l_{2} = (2.5 \cdot 300) /1.5 = 500 cm .

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In a potentiometer experiment, the balancing length for a cell of EMF ε1​=1.5V is l1​=300cm. If the cell is replaced by another cell of EMF ε2​=2.5V, what will be the new balancing length l2​?

Solution

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More Current Electricity practice questions

$In a potentiometer experiment, the balancing length for a cell of EMF ε_{1} = 1.5 V is l_{1} = 300 cm . If the cell is replaced by another cell of EMF ε_{2} = 2.5 V, what will be the new balancing length l_{2} ?$