A particle starts from rest and accelerates at 3 meters per second squared. How much distance does it cover in 2 seconds?

B. 6 m — Using the kinematic equation s equals ut plus one half at squared, with u equal to 0, a equal to 3, and t equal to 2. This gives s equals 0 plus 0.5 times 3 times 4, which is 6 meters.

JEE Advanced · PhysicsEasy

$A particle starts from rest (u = 0) and accelerates at a = 3 m/s^{2} . How much distance does it cover in t = 2 s ?$

A. $3 m$
B. $6 m$
C. $9 m$
D. $12 m$

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Correct answer: B — $6 m$

Solution

Using s = u t + (1/2) a t^{2}, with u = 0, a = 3 m/s^{2}, and t = 2 s . This gives s = 0 + (0.5) (3) (2^{2}) = 6 m .

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A particle starts from rest (u=0) and accelerates at a=3 m/s2. How much distance does it cover in t=2 s?

Solution

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More Kinematics practice questions

$A particle starts from rest (u = 0) and accelerates at a = 3 m/s^{2} . How much distance does it cover in t = 2 s ?$