If the pressure of an ideal gas is doubled and the volume is halved, the temperature of the gas will

Solution

1. The ideal gas law is given by $PV=nRT$.
2. When the pressure is doubled ($2P$) and the volume is halved ($V/2$), the new product is $(2P)(V/2)=PV$.
3. Since the product $PV$ remains constant and $n$ and $R$ are constant, the temperature $T$ must remain unchanged.
4. Hence the answer is (A).