Two blocks of masses $m_1=3\text{ kg}$ and $m_2=2\text{ kg}$ are connected by a light string passing over a frictionless pulley. The system is released from rest. What is the tension $T$ in the string? (Take $g=10{\text{ m/s}}^2$)

Solution

1. Identify the given values: $m_1=3\text{ kg}$, $m_2=2\text{ kg}$, and $g=10{\text{ m/s}}^2$.
2. Calculate the acceleration of the system using $$\begin{array}{rl}a& =\frac{(m_1-m_2)g}{m_1+m_2}\\ & =\frac{(3-2)\times 10}{3+2}\\ & =2{\text{ m/s}}^2\end{array}$$.
3. Determine the tension $T$ using the equation $$\begin{array}{rl}T& =m_2(g+a)\\ & =2(10+2)\\ & =24\text{ N}\end{array}$$.
4. Hence the answer is (B).