What is the magnetic field at the center of a circular coil of radius R carrying current I?

A. B = _0 I2R — Using the Biot-Savart law for a circular loop, the magnetic field at the center is derived as B = mu0 * I / (2 * R). This is a standard result for a single turn coil.

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$What is the magnetic field B at the center of a circular coil of radius R carrying current I ?$

A. $B = \frac{μ _{0} I}{2 R}$
B. $B = \frac{μ _{0} I}{4 R}$
C. $B = \frac{μ _{0} I}{2 π R}$
D. $B = μ_{0} I R$

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Correct answer: A — $B = \frac{μ _{0} I}{2 R}$

Solution

Using the Biot-Savart law for a circular loop, the magnetic field at the center is derived as B = \frac{μ _{0} I}{2 R} . This is a standard result for a single turn coil.

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What is the magnetic field B at the center of a circular coil of radius R carrying current I?

Solution

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$What is the magnetic field B at the center of a circular coil of radius R carrying current I ?$