JEE Advanced · PhysicsMedium

$The de Broglie wavelength λ of an electron accelerated through a potential difference of V = 100 V is approximately:$

A. $0.123 nm$
B. $1.23 nm$
C. $0.0123 nm$
D. $12.3 nm$

Show correct answer & step-by-step solution

Correct answer: A — $0.123 nm$

Solution

The de Broglie wavelength for an electron is given by λ = 1.227/ V nm. Substituting V = 100, we get λ = 1.227/10 = 0.1227 nm.

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The de Broglie wavelength of an electron accelerated through a potential differe… — JEE Advanced Physics Question with Solution |