In a spring-mass system, if the mass is doubled while the spring constant remains the same, how does the time period change?

A. 2 times — The time period of a spring-mass system is T = 2 * pi * sqrt(m/k). If m is replaced by 2m, the new time period becomes sqrt(2) times the original.

JEE Advanced · PhysicsEasy

$In a spring-mass system, if the mass m is doubled while the spring constant k remains the same, how does the time period T change?$

A. $2 times$
B. $2 times$
C. $Remains the same$
D. $1/ 2 times$

Show correct answer & step-by-step solution

Correct answer: A — $2 times$

Solution

The time period of a spring-mass system is T = 2 π \frac{m}{k} . If m is replaced by 2 m, the new time period becomes 2 times the original.

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