JEE Main · ChemistryHard

$The isoelectric point of an amino acid is the pH at which the molecule exists primarily as a zwitterion. For an amino acid with pKa_{1} = 2.3 and pKa_{2} = 9.7, what is the isoelectric point?$

A. $6.0$
B. $7.4$
C. $12.0$
D. $3.7$

Show correct answer & step-by-step solution

Correct answer: A — $6.0$

Solution

$The isoelectric point pI is calculated as pI = (pKa_{1} + pKa_{2}) /2 .$
$Substitute the given values: pI = (2.3 + 9.7) /2 .$
$Calculate the sum: $12.0 / 2 = 6.0$.$
$Hence the answer is (A).$

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