JEE Main · ChemistryHard

$In the reaction 3 Br_{2} + 6 CO_{3}^{2 -} + 3 H_{2} O \to 5 Br^{-} + BrO_{3}^{-} + 6 HCO_{3}^{-}, what is the change in oxidation state of bromine?$

A. $0 to - 1 and 0 to + 5$
B. $0 to - 1 and 0 to + 3$
C. $- 1 to 0 and + 5 to 0$
D. $0 to - 2 and 0 to + 6$

Show correct answer & step-by-step solution

Correct answer: A — $0 to - 1 and 0 to + 5$

Solution

$The reactant is elemental bromine Br_{2} where oxidation state is 0 .$
$The product Br^{-} has oxidation state - 1 .$
$The product BrO_{3}^{-} has oxidation state x + 3 (- 2) = - 1, so x = + 5 .$
$The reaction is a disproportionation of Br_{2} .$
$Hence the answer is (A).$

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