For the adsorption of a gas on a solid surface, the Freundlich adsorption isotherm is given by x/m = kP^(1/n). Which of the following statements is correct regarding this isotherm?

A. As pressure increases, the value of 1/n approaches zero. — At high pressure, the adsorption becomes independent of pressure, meaning 1/n approaches zero.

B. The value of 1/n can be greater than 1.

C. The isotherm is valid only at high pressure.

D. The value of 1/n is always equal to 1.

JEE Main · ChemistryMedium

$For the adsorption of a gas on a solid surface, the Freundlich adsorption isotherm is given by \frac{x}{m} = k P^{1/ n} . Which of the following statements is correct regarding this isotherm?$

A. $As pressure increases, the value of 1/ n approaches zero.$
B. $The value of 1/ n can be greater than 1 .$
C. $The isotherm is valid only at high pressure.$
D. $The value of 1/ n is always equal to 1 .$

Show correct answer & step-by-step solution

Correct answer: A — $As pressure increases, the value of 1/ n approaches zero.$

Solution

$The Freundlich isotherm is \frac{x}{m} = k P^{1/ n} .$
$At low pressure, $1/n = 1$, making the adsorption directly proportional to pressure.$
$At high pressure, the surface becomes saturated and adsorption becomes independent of pressure.$
$This implies P^{1/ n} becomes constant, so 1/ n must approach 0 .$
$Hence the answer is (A).$

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For the adsorption of a gas on a solid surface, the Freundlich adsorption isotherm is given by mx​=kP1/n. Which of the following statements is correct regarding this isotherm?

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$For the adsorption of a gas on a solid surface, the Freundlich adsorption isotherm is given by \frac{x}{m} = k P^{1/ n} . Which of the following statements is correct regarding this isotherm?$