JEE Main · ChemistryEasy
The first law of thermodynamics for a closed system is expressed as:
- A.
- B.
- C.
- D.
Show correct answer & step-by-step solution
Correct answer: A —
Solution
- The first law of thermodynamics relates internal energy, heat, and work.
- The change in internal energy is equal to the heat added to the system plus the work done on the system .
- The standard IUPAC sign convention leads to the equation .
- Hence the answer is (A).
Attempt this question & track your score
Sign up free to answer, get instant scoring, and let SolveGini track which Chemistry topics you need to revise.
Attempt & Track Free →More Thermodynamics practice questions
- Which of the following is an extensive property of a thermodynamic system?
- Which of the following is a state function?
- For an adiabatic process, which of the following conditions is always true?
- For a reaction to be spontaneous at constant temperature and pressure, the change in Gibbs free energy must be:
- The standard enthalpy of formation of carbon dioxide is -393.5 kJ per mole. Calculate the heat released when 88 grams of
- For a reaction at 298 K, the enthalpy change is -20 kJ per mole and the entropy change is -50 J per Kelvin per mole. Cal
- The entropy change for the transition of liquid water to steam at 100 degrees Celsius is 109 J per Kelvin per mole. Calc
- For the reaction 2A + B goes to 2C, the change in internal energy is -10.5 kJ at 300 K. Calculate the change in enthalpy
- Calculate the work done during the isothermal reversible expansion of 2 moles of an ideal gas from 10 L to 20 L at 300 K
- The enthalpy of combustion of carbon to carbon dioxide is -393.5 kJ/mol. Calculate the heat released upon forming 35.2 g
- For a reversible adiabatic expansion of 1 mole of an ideal gas with heat capacity ratio gamma, the change in entropy of
- Calculate the standard Gibbs free energy change for the reaction 2A + B goes to 3Cat 298 K, given the equilibrium consta