Find the midpoint of the line segment joining (2, 4, 6) and (4, 6, 8).

C. (3, 5, 7) — The midpoint is the average of the coordinates of the endpoints.

JEE Main · MathematicsEasy

$Find the midpoint of the line segment joining A (2, 4, 6) and B (4, 6, 8) .$

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Correct answer: C — $(3, 5, 7)$

$The midpoint formula is (\frac{x _{1} + x _{2}}{2}, \frac{y _{1} + y _{2}}{2}, \frac{z _{1} + z _{2}}{2}) .$
$Substitute the coordinates: (\frac{2 + 4}{2}, \frac{4 + 6}{2}, \frac{6 + 8}{2}) .$
$Calculate the sums: (\frac{6}{2}, \frac{10}{2}, \frac{14}{2}) .$
$Simplify the fractions: .$
$Hence the answer is (C).$

$Find the direction cosines of the vector (1, 2, 2).$
$Find the distance between the points P(1, 2, 3) and Q(4, 6, 3).$
$What is the equation of the plane passing through the point (1, 1, 1) and perpendicular to the vector (1, 0, 0)?$
$Find the midpoint of the line segment joining (2, 4, 6) and (4, 2, 0).$
$The distance of the point (1, -2, 3) from the plane passing through the points (1, 2, 3), (-1, 3, 0), and (2, 1, -1) is:$
$The equation of the plane passing through the intersection of the planes x + y + z = 6 and 2x + 3y + 4z + 5 = 0 and the$
$Find the shortest distance between the lines (x-1)/2 = (y-2)/3 = (z-3)/4 and (x-2)/3 = (y-4)/4 = (z-5)/5.$
$The angle between the line (x-1)/2 = (y-2)/1 = (z+3)/-2 and the plane x + y + 4z = 9 is:$
$The angle between the line (x-1)/1 = (y-2)/2 = (z-3)/3 and the plane x + y + z = 0 is:$
$Find the image of the point (1, 2, 3) in the plane x + y + z = 6.$
$Find the equation of the sphere which has its center at (1, 2, 3) and touches the plane 2x - y + 2z = 0.$
$Find the distance between the points P(1, 2, 3) and Q(3, 4, 5).$