What is the real part of the complex number 7 - 9i?

C. 7 — A complex number is written in the form a + bi, where a is the real part and b is the imaginary part. In the number 7 - 9i, the real part is 7.

JEE Main · MathematicsEasy

$What is the real part of the complex number z = 7 - 9 i ?$

A. $9$
B. $- 9$
C. $7$
D. $- 7$

Show correct answer & step-by-step solution

Correct answer: C — $7$

Solution

A complex number is expressed as z = a + bi, where a is the real part. For z = 7 - 9 i, the real part is 7 .

Attempt this question & track your score

Attempt & Track Free →

More Complex Numbers practice questions

$Find the modulus of the complex number 3 + 4i.$
$Simplify the expression (1 + i) + (2 - 3i).$
$What is the conjugate of the complex number 2 - 5i?$
$What is the value of i raised to the power of 402?$
$If z is a complex number such that |z - 3| + |z + 3| = 8, then the maximum value of |z| is$
$The amplitude of the complex number (1 + i sqrt(3)) / (sqrt(3) + i) is$
$If z = x + iy satisfies |z + 1| = |z - 1|, then the locus of z is$
$I f o m e g ai s a co m pl e x c u b er oo t o f u ni t y, t h e n t h e v a l u eo f (1 + o m e g a - o m e g a s q u a r e d)^{7} i s$
$I f t h eco m pl e x n u mb er sz 1, z 2, an d z 3 r e p r ese n tt h e v er t i ceso f an e q u i l a t er a l t r ian g l e, t h e n z 1^{2} + z 2^{2} + z 3^{2} e q u a l s$
$T h e n u mb er o f co m pl e x n u mb er sz s u c h t ha t ∣ z ∣ = 1 an d ∣ z^{4} + z^{3} + z^{2} + z + 1∣ = 0 i s$
$If z1 and z2 are two complex numbers such that |z1 + z2| = |z1| + |z2|, then arg(z1) - arg(z2) is$
$L e t z b e a co m pl e x n u mb er s a t i s f y in g ∣ z^{2} - 1∣ = ∣ z ∣^{2} + 1. T h e n z l i eso n$

View all Complex Numbers questions →

What is the real part of the complex number z=7−9i?

Solution

Attempt this question & track your score

More Complex Numbers practice questions

$What is the real part of the complex number z = 7 - 9 i ?$