JEE Main · MathematicsEasy

$What is the center of the circle given by the equation (x - 1)^{2} + (y + 2)^{2} = 9 ?$

A. $(1, 2)$
B. $(- 1, 2)$
C. $(1, - 2)$
D. $(- 1, - 2)$

Show correct answer & step-by-step solution

Correct answer: C — $(1, - 2)$

Solution

$The standard form of a circle is (x - h)^{2} + (y - k)^{2} = r^{2} .$
$Comparing (x - 1)^{2} + (y + 2)^{2} = 9 to the standard form.$
$We identify h = 1 and k = - 2 .$
$The center is (h, k) = (1, - 2) .$
$Hence the answer is (C).$

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