JEE Main · MathematicsEasy

$lim_{x \to 2} \frac{x ^{2} - 4}{x - 2}$

A. $0$
B. $2$
C. $4$
D. $Does not exist$

Show correct answer & step-by-step solution

Correct answer: C — $4$

Solution

\frac{x ^{2} - 4}{x - 2} = \frac{( x - 2 ) ( x + 2 )}{x - 2} = x + 2 . Substituting x = 2 gives 2 + 2 = 4 .

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