JEE Main · MathematicsHard

$If the roots of the equation x^{2} - b x + c = 0 are two consecutive integers, then the value of b^{2} - 4 c is:$

A. $0$
B. $1$
C. $2$
D. $4$

Show correct answer & step-by-step solution

Correct answer: B — $1$

Solution

Let the roots be k and k + 1 . The discriminant D = b^{2} - 4 c is equal to the square of the difference of the roots, which is (k + 1 - k)^{2} = 1^{2} = 1 .

Attempt this question & track your score

Sign up free to answer, get instant scoring, and let SolveGini track which Mathematics topics you need to revise.

Attempt & Track Free →

More Quadratic Equations practice questions

$Which of the following is a root of the equation x squared minus 9 equals 0?$
$Find the roots of the quadratic equation x squared minus 5x plus 6 equals 0.$
$If the sum of the roots of the equation x squared minus kx plus 8 equals 0 is 6, find the value of k.$
$What is the discriminant of the quadratic equation 2x squared plus 4x plus 1 equals 0?$
$Find the product of the roots of the equation 3x squared plus 5x minus 2 equals 0.$
$The set of all values of k for which the quadratic equation x squared plus 2(k minus 1)x plus k plus 5 equals 0 has root$
$The number of real solutions of the equation x squared minus 3 times absolute value of x plus 2 equals 0 is$
$If alpha and beta are the roots of the equation x squared minus 6x plus 2 equals 0, then the value of alpha to the power$
$If the roots of the equation x squared minus bx plus c equals 0 are two consecutive integers, then b squared minus 4c eq$
$If alpha and beta are the roots of the equation x squared minus 6x plus 2 equals 0, and a sub n equals alpha to the powe$
$Let p and q be real numbers such that p is not equal to 0. If the equations x squared plus px plus q equals 0 and x squa$
$The number of real solutions of the equation x squared minus 2 times absolute value of x minus 3 equals 0 is:$

View all Quadratic Equations questions →