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$A carrier wave of peak voltage A_{c} = 12 V is modulated by a sinusoidal signal to a depth of μ = 0.5 . Calculate the peak voltages of the upper sideband (A_{U S B}) and lower sideband (A_{L S B}).$

A. $3 V and 3 V$
B. $6 V and 6 V$
C. $1.5 V and 1.5 V$
D. $4 V and 4 V$

Show correct answer & step-by-step solution

Correct answer: A — $3 V and 3 V$

Solution

$The amplitude of each sideband is A_{S B} = μ A_{c} /2 .$
$Substitute μ = 0.5 and A_{c} = 12 V .$
$A_{S B} = (0.5 \times 12) /2 .$
$A_{S B} = 6/2 = 3 V .$
$Hence the answer is (A).$

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