A receiver is connected to an antenna with an effective aperture of 5 square meters. If the incident power density of the electromagnetic wave is 10 microwatts per square meter, what is the power received?

A. 50 micro-watts — The power received by an antenna is the product of the incident power density and the effective aperture of the antenna. P_r = S * A_e.

JEE Main · PhysicsHard

$A receiver is connected to an antenna with an effective aperture of A_{e} = 5 m^{2} . If the incident power density of the electromagnetic wave is S = 10 μ W/m^{2}, what is the power received P_{r} ?$

A. $50 micro-watts$
B. $2 micro-watts$
C. $500 micro-watts$
D. $0.5 micro-watts$

Show correct answer & step-by-step solution

Correct answer: A — $50 micro-watts$

Solution

P_{r} = S \times A_{e} = 10 μ W/m^{2} \times 5 m^{2} = 50 μ W .

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A receiver is connected to an antenna with an effective aperture of Ae​=5 m2. If the incident power density of the electromagnetic wave is S=10 μW/m2, what is the power received Pr​?

Solution

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More Communication Systems practice questions

$A receiver is connected to an antenna with an effective aperture of A_{e} = 5 m^{2} . If the incident power density of the electromagnetic wave is S = 10 μ W/m^{2}, what is the power received P_{r} ?$