JEE Main · PhysicsHard

$A receiver is connected to an antenna with an effective height of h_{e} = 50 m . If the electric field intensity of the incident electromagnetic wave is E = 2 \times 1 0^{- 6} V/m, calculate the induced EMF ϵ in the antenna.$

A. $100 microvolts$
B. $50 microvolts$
C. $25 microvolts$
D. $10 microvolts$

Show correct answer & step-by-step solution

Correct answer: A — $100 microvolts$

Solution

$The induced EMF is given by ϵ = E \times h_{e} .$
$Substitute the values: ϵ = (2 \times 1 0^{- 6} V/m) \times (50 m) .$
$Calculate the product: ϵ = 100 \times 1 0^{- 6} V = 100 μ V .$
$Hence the answer is (A).$

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