JEE Main · PhysicsHard

$For a sky wave propagation, the critical frequency of the ionospheric layer is f_{c} = 10 MHz . Calculate the maximum usable frequency M U F for a signal transmitted at an angle of incidence of θ = 4 5^{\circ} .$

A. $10 MHz$
B. $14.14 MHz$
C. $20 MHz$
D. $7.07 MHz$

Show correct answer & step-by-step solution

Correct answer: B — $14.14 MHz$

Solution

$The formula is M U F = f_{c} / cos (θ) .$
$Substitute the values: M U F = 10 MHz / cos (4 5^{\circ}) .$
$Calculate the value: M U F = 10/ (1/ 2) = 10 \times 1.414 = 14.14 MHz .$
$Hence the answer is (B).$

Attempt this question & track your score

Sign up free to answer, get instant scoring, and let SolveGini track which Physics topics you need to revise.

Attempt & Track Free →

More Communication Systems practice questions

View all Communication Systems questions →