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A square loop of side $a = 0.1 \text{ m}$ and resistance $R = 0.5 \, \Omega$ is moved out of a magnetic field $B = 1 \text{ T}$ at a constant velocity $v = 2 \text{ m/s}$. What is the power $P$ dissipated as heat in the loop?
- A.$0.08 \text{ W}$
- B.$0.04 \text{ W}$
- C.$0.16 \text{ W}$
- D.$0.02 \text{ W}$
Show correct answer & step-by-step solution
Correct answer: A — $0.08 \text{ W}$
Solution
The induced EMF is . The power dissipated is .
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