JEE Main · PhysicsHard
A plane electromagnetic wave of frequency $f = 50 \text{ MHz}$ travels in free space along the positive $x$-direction. At a particular point in space and time, the electric field is $\vec{E} = 6.3 \hat{j} \text{ V/m}$. What is the corresponding magnetic field vector $\vec{B}$ at this point?
- A.$2.1 \times 10^{-8} \hat{k} \text{ T}$
- B.$-2.1 \times 10^{-8} \hat{k} \text{ T}$
- C.$1.89 \times 10^{-7} \hat{k} \text{ T}$
- D.$-1.89 \times 10^{-7} \hat{k} \text{ T}$
Show correct answer & step-by-step solution
Correct answer: A — $2.1 \times 10^{-8} \hat{k} \text{ T}$
Solution
The magnitude is . Since and the wave travels in , , so must be in the direction.
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