JEE Main · PhysicsHard
A container of volume $V$ is divided into two parts by a partition. One part contains $n$ moles of an ideal gas at temperature $T$ in volume $V_1$, and the other is vacuum with volume $V_2$. If the partition is removed, what is the change in entropy $\Delta S$?
- A.$nR \ln(\frac{V_1}{V_2})$
- B.$nR \ln(\frac{V_1+V_2}{V_1})$
- C.$nR \ln(\frac{V_2}{V_1})$
- D.$0$
Show correct answer & step-by-step solution
Correct answer: B — $nR \ln(\frac{V_1+V_2}{V_1})$
Solution
For free expansion, . .
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