JEE Main · PhysicsHard
The mean free path of a gas molecule is $\lambda = \frac{kT}{\sqrt{2}\pi d^2 P}$. If the temperature $T$ is doubled and the pressure $P$ is halved, what is the new mean free path $\lambda'$?
- A.$\lambda$
- B.$2\lambda$
- C.$4\lambda$
- D.$\lambda/4$
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Correct answer: C — $4\lambda$
Solution
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