If the velocity of a body is doubled, its kinetic energy becomes how many times its original value?

B. 4 — Since kinetic energy is proportional to the square of velocity, doubling the velocity results in a factor of two squared, which is four.

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$If the velocity $v$ of a body is doubled, its kinetic energy $K$ becomes how many times its original value?$

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Correct answer: B — $$4$$

Since

K \propto v^{2}

, if

v

becomes

2 v

, then

K^{'} \propto (2 v)^{2} = 4 v^{2}

. Thus, the kinetic energy becomes

4

times the original value.