JEE Advanced · PhysicsEasy

$Three resistors of R_{1} = 1 Ω, R_{2} = 2 Ω, and R_{3} = 3 Ω are connected in series. What is the total resistance R_{t o t a l} ?$

A. $0.54 Ω$
B. $1 Ω$
C. $5 Ω$
D. $6 Ω$

Show correct answer & step-by-step solution

Correct answer: D — $6 Ω$

Solution

$The formula for series resistance is R_{t o t a l} = R_{1} + R_{2} + R_{3} .$
$Substituting the values, R_{t o t a l} = 1 + 2 + 3 .$
$Calculating the sum, R_{t o t a l} = 6 Ω .$
$Hence the answer is (D).$

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