According to VSEPR theory, what is the shape of the ${\text{ClF}}_3$ molecule?

Solution

1. The central atom $\text{Cl}$ has 7 valence electrons and forms 3 bonds with $\text{F}$ atoms.
2. The number of lone pairs is $(7-3)/2=2$.
3. The steric number is $3 + 2 = 5$, leading to $s{p}^{3}d$ hybridization with trigonal bipyramidal electron geometry.
4. The two lone pairs occupy equatorial positions to minimize repulsion, resulting in aT-shaped molecular geometry.
5. Hence the answer is (B).