JEE Main · ChemistryHard

$Which of the following statements regarding the stability of oxidation states of lanthanides is correct?$

A. $Ce^{4 +} is a strong reducing agent.$
B. $Eu^{2 +} is a strong oxidizing agent.$
C. $Tb^{4 +} is stable due to half-filled f -orbital configuration.$
D. $Sm^{2 +} is a stable ion in aqueous solution.$

Show correct answer & step-by-step solution

Correct answer: C — $Tb^{4 +} is stable due to half-filled f -orbital configuration.$

Solution

$The atomic number of Tb is 65.$
$The electronic configuration of Tb^{4 +} is [Xe] 4 f^{7} .$
$The 4 f^{7} configuration is half-filled and provides extra stability.$
$Hence the answer is (C).$

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