Identify the product formed when ${\text{CH}}_3{\text{C(CH}}_3)={\text{CHCH}}_3$ is treated with ${\text{O}}_3$ followed by ${\text{Zn/H}}_2\text{O}$.

Solution

1. Ozonolysis involves the cleavage of the $\text{C}=\text{C}$ double bond.
2. The structure ${\text{CH}}_3{\text{C(CH}}_3)={\text{CHCH}}_3$ splits at the double bond.
3. The left fragment ${\text{CH}}_3{\text{C(CH}}_3)$ becomes ${\text{CH}}_3{\text{COCH}}_3$.
4. The right fragment ${\text{CHCH}}_3$ becomes ${\text{CH}}_3\text{CHO}$.
5. Hence the answer is (A).