What is the product formed when sodium metal reacts with excess oxygen at high temperature: ${\text{Na}}_2\text{O}$, ${\text{Na}}_2{\text{O}}_2$, ${\text{NaO}}_2$, or ${\text{Na}}_2{\text{O}}_3$?

Solution

1. Sodium burns in oxygen to form different oxides depending on the conditions.
2. With limited oxygen, ${\text{Na}}_2\text{O}$ is formed.
3. With excess oxygen at high temperature, the reaction is $2\text{Na}+{\text{O}}_2\to {\text{Na}}_2{\text{O}}_2$.
4. Hence the answer is (B).