For a Freundlich adsorption isotherm, the plot of $\log (x/m)$ versus $\log (P)$ is a straight line with a slope equal to:

Solution

1. The Freundlich isotherm equation is $\frac{x}{m}=k{P}^{1/n}$.
2. Taking the logarithm on both sides gives $\log (\frac{x}{m})=\log (k)+\frac{1}{n}\log (P)$.
3. This equation follows the linear form $y=mx+c$, where the slope is $\frac{1}{n}$.
4. Hence the answer is (B).