If A and B are two sets such that A has 4 elements and B has 3 elements, what is the number of subsets of the Cartesian product Across B?

B. 2^12 — The number of elements in the Cartesian product A x B is n(A) * n(B) = 4 * 3 = 12. The number of subsets of a set with n elements is 2^n, so the answer is 2^12.

JEE Main · MathematicsMedium

$If A and B are two sets such that n (A) = 4 and n (B) = 3, what is the number of subsets of the Cartesian product A \times B ?$

A. $2^{7}$
B. $2^{1} 2$
C. $12$
D. $2^{4}$

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Correct answer: B — $2^{1} 2$

Solution

n (A \times B) = n (A) \times n (B) = 4 \times 3 = 12 . The number of subsets is 2^{n (A \times B)} = 2^{12} .

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If A and B are two sets such that n(A)=4 and n(B)=3, what is the number of subsets of the Cartesian product A×B?

Solution

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More Sets & Relations practice questions

$If A and B are two sets such that n (A) = 4 and n (B) = 3, what is the number of subsets of the Cartesian product A \times B ?$