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A wire of resistance $R = 10 \text{ } \Omega$ is stretched to double its original length. What is the new resistance of the wire?
- A.$10 \text{ } \Omega$
- B.$20 \text{ } \Omega$
- C.$40 \text{ } \Omega$
- D.$80 \text{ } \Omega$
Show correct answer & step-by-step solution
Correct answer: C — $40 \text{ } \Omega$
Solution
Since volume is constant, stretching the wire to results in . Using , the new resistance becomes .
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