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A wire of resistance $R = 10 \, \Omega$ is stretched to twice its original length. What is the new resistance of the wire?
- A.$20 \, \Omega$
- B.$40 \, \Omega$
- C.$10 \, \Omega$
- D.$5 \, \Omega$
Show correct answer & step-by-step solution
Correct answer: B — $40 \, \Omega$
Solution
Since volume is constant, when . Resistance , so .
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