JEE Main · PhysicsHard
A circular loop of radius $r$ is placed in a magnetic field $B = B_0(1 - t/T)$ directed perpendicular to the plane. The induced current in the loop with resistance $R$ is?
- A.$\frac{B_0 \pi r^2}{RT}$
- B.$\frac{B_0 \pi r^2}{R}$
- C.$\frac{B_0 \pi r^2 T}{R}$
- D.$\frac{B_0 \pi r^2}{2RT}$
Show correct answer & step-by-step solution
Correct answer: A — $\frac{B_0 \pi r^2}{RT}$
Solution
The induced emf is . Since , the derivative is . The current is the magnitude of emf divided by , giving .
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