A conducting rod of length 1 meter moves with a velocity of 2 meters per second perpendicular to a uniform magnetic field of 0.5 Tesla. What is the induced electromotive force across the rod?

B. 1.0 V — The motional electromotive force induced in a conductor moving through a magnetic field is given by the formula epsilon equals B times l times v. Substituting the given values, we get 0.5 times 1 times 2, which equals 1.0 Volts.

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$A conducting rod of length l = 1 m moves with a velocity v = 2 m/s perpendicular to a uniform magnetic field B = 0.5 T . What is the induced electromotive force ε across the rod?$

A. $0.5 V$
B. $1.0 V$
C. $2.0 V$
D. $2.5 V$

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Correct answer: B — $1.0 V$

Solution

The motional EMF is given by ε = B l v . Substituting the values, ε = 0.5 \times 1 \times 2 = 1.0 V .

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A conducting rod of length l=1 m moves with a velocity v=2 m/s perpendicular to a uniform magnetic field B=0.5 T. What is the induced electromotive force ε across the rod?

Solution

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More Electromagnetic Induction practice questions

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