JEE Main · PhysicsMedium

$In an electromagnetic wave, the amplitude of the magnetic field is B_{0} = 3 \times 1 0^{- 10} T . What is the amplitude of the electric field E_{0} associated with this wave in vacuum?$

A. $0.09 V/m$
B. $0.9 V/m$
C. $9 V/m$
D. $0.009 V/m$

Show correct answer & step-by-step solution

Correct answer: A — $0.09 V/m$

Solution

$The relation between amplitudes is E_{0} = c B_{0} .$
$Using c = 3 \times 1 0^{8} m/s and B_{0} = 3 \times 1 0^{- 10} T .$
$Calculating E_{0} = (3 \times 1 0^{8}) \times (3 \times 1 0^{- 10}) .$
$This results in E_{0} = 9 \times 1 0^{- 2} V/m = 0.09 V/m .$
$Hence the answer is (A).$

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