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$The intensity of a plane electromagnetic wave is I = 0.02 W/m^{2} . What is the radiation pressure P exerted by this wave on a perfectly absorbing surface?$

A. $6.67 \times 1 0^{- 11} Pa$
B. $1.33 \times 1 0^{- 10} Pa$
C. $3.33 \times 1 0^{- 11} Pa$
D. $2.00 \times 1 0^{- 10} Pa$

Show correct answer & step-by-step solution

Correct answer: A — $6.67 \times 1 0^{- 11} Pa$

Solution

$For a perfectly absorbing surface, the radiation pressure is P = I / c .$
$Given I = 0.02 W/m^{2} and c = 3 \times 1 0^{8} m/s .$
$Calculating P = 0.02/ (3 \times 1 0^{8}) Pa .$
$This yields P = 0.667 \times 1 0^{- 10} Pa = 6.67 \times 1 0^{- 11} Pa .$
$Hence the answer is (A).$

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