A fish in a pond at a depth of 20 cm looks up at a bird flying at a height of 30 cm above the water surface. What is the apparent distance of the bird as seen by the fish?

B. 60 cm — The fish sees the bird at an apparent height. The height of the bird is magnified by the refractive index of water when viewed from within the medium.

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$A fish in a pond at a depth of d_{1} = 20 cm looks up at a bird flying at a height h = 30 cm above the water surface (μ = 4/3). What is the apparent distance of the bird as seen by the fish?$

A. $50 cm$
B. $60 cm$
C. $40 cm$
D. $70 cm$

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Correct answer: B — $60 cm$

Solution

Apparent height h^{'} = μ \times h = (4/3) \times 30 = 40 cm . Total distance = d_{1} + h^{'} = 20 + 40 = 60 cm .

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A fish in a pond at a depth of d1​=20 cm looks up at a bird flying at a height h=30 cm above the water surface (μ=4/3). What is the apparent distance of the bird as seen by the fish?

Solution

Attempt this question & track your score

More Ray Optics practice questions

$A fish in a pond at a depth of d_{1} = 20 cm looks up at a bird flying at a height h = 30 cm above the water surface (μ = 4/3). What is the apparent distance of the bird as seen by the fish?$