JEE Main · PhysicsMedium
A ray of light enters a glass slab of thickness $t = 10 \text{ cm}$ and refractive index $\mu = 1.5$ at an angle of incidence $i = 45^\circ$. What is the lateral shift $d$ produced by the slab?
- A.10(1 - 1/sqrt(2)) cm
- B.10(1 - sqrt(2/3)) cm
- C.5(1 - sqrt(2/3)) cm
- D.10(1 - sqrt(3/2)) cm
Show correct answer & step-by-step solution
Correct answer: B — 10(1 - sqrt(2/3)) cm
Solution
Using and , we calculate the shift.
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