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A thin circular ring of mass $M$ and radius $R$ is rotating about its axis with angular velocity $\omega$. What is the torque required to stop it in $t$ seconds?
- A.$\frac{MR^2\omega}{t}$
- B.$\frac{MR^2\omega}{2t}$
- C.$\frac{2MR^2\omega}{t}$
- D.$\frac{MR^2\omega}{4t}$
Show correct answer & step-by-step solution
Correct answer: A — $\frac{MR^2\omega}{t}$
Solution
Torque . For a ring, . Thus, .
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