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A uniform rod of length $L$ and mass $M$ is pivoted at one end and allowed to swing in a vertical plane. What is the angular frequency of small oscillations?
- A.$\sqrt{\frac{3g}{2L}}$
- B.$\sqrt{\frac{g}{L}}$
- C.$\sqrt{\frac{2g}{3L}}$
- D.$\sqrt{\frac{3g}{L}}$
Show correct answer & step-by-step solution
Correct answer: A — $\sqrt{\frac{3g}{2L}}$
Solution
For a physical pendulum, . With and , we find .
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