A body of mass 2 kg is dropped from a height of 10 meters. What is its kinetic energy just before it hits the ground?

B. 200 J — By the law of conservation of energy, the potential energy at the top is converted entirely into kinetic energy at the bottom. The potential energy is mgh.

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$A body of mass m = 2 kg is dropped from a height of h = 10 m . What is its kinetic energy just before it hits the ground? (Take g = 10 m/s^{2})$

A. $100 J$
B. $200 J$
C. $50 J$
D. $400 J$

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Correct answer: B — $200 J$

Solution

P E = m g h = 2 \times 10 \times 10 = 200 J . Thus, K E = 200 J .

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A body of mass m=2 kg is dropped from a height of h=10 m. What is its kinetic energy just before it hits the ground? (Take g=10 m/s2)

Solution

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More Work Energy Power practice questions

$A body of mass m = 2 kg is dropped from a height of h = 10 m . What is its kinetic energy just before it hits the ground? (Take g = 10 m/s^{2})$