NEET · BiologyHard
In a dihybrid cross between two heterozygous individuals for two genes showing independent assortment, what is the probability that an offspring will show the dominant phenotype for both traits but be heterozygous for both genes?
- A.
- B.
- C.
- D.
Show correct answer & step-by-step solution
Correct answer: C —
Solution
- The cross is .
- The probability of genotype is and is .
- Since the genes assort independently, the probability of is .
- Converting to a denominator of 16, $1/4 = 4/16$.
- Hence the answer is (C).
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