A particle is moving in a circle of radius 2 meters with a constant angular velocity of 3 radians per second. What is the linear velocity of the particle in meters per second?

B. 6 — The linear velocity is related to angular velocity by the formula v equals r times omega. Substituting the given values, v equals 2 times 3, which results in 6 meters per second.

JEE Advanced · PhysicsEasy

$A particle is moving in a circle of radius r = 2 m with a constant angular velocity of ω = 3 rad/s . What is the linear velocity v of the particle in m/s ?$

A. $3$
B. $6$
C. $9$
D. $1.5$

Show correct answer & step-by-step solution

Correct answer: B — $6$

Solution

The linear velocity is related to angular velocity by the formula v = r ω . Substituting the given values, v = 2 \times 3 = 6 m/s .

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A particle is moving in a circle of radius r=2 m with a constant angular velocity of ω=3 rad/s. What is the linear velocity v of the particle in m/s?

Solution

Attempt this question & track your score

More Rotational Motion practice questions

$A particle is moving in a circle of radius r = 2 m with a constant angular velocity of ω = 3 rad/s . What is the linear velocity v of the particle in m/s ?$