If the angular velocity of a rotating body increases from 2 radians per second to 8 radians per second in 3 seconds, what is the angular acceleration in radians per second squared?

D. 2 — Angular acceleration is defined as the change in angular velocity divided by the time interval. Here, the change is 8 minus 2, which is 6, and dividing by 3 seconds gives 2 radians per second squared.

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$If the angular velocity of a rotating body increases from ω_{i} = 2 rad/s to ω_{f} = 8 rad/s in t = 3 s, what is the angular acceleration α in rad/s^{2} ?$

A. $1$
B. $3$
C. $4$
D. $2$

Show correct answer & step-by-step solution

Correct answer: D — $2$

Solution

Angular acceleration is defined as α = \frac{ω _{f} - ω _{i}}{t} . Substituting the values, α = \frac{8 - 2}{3} = \frac{6}{3} = 2 rad/s^{2} .

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If the angular velocity of a rotating body increases from ωi​=2 rad/s to ωf​=8 rad/s in t=3 s, what is the angular acceleration α in rad/s2?

Solution

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More Rotational Motion practice questions

$If the angular velocity of a rotating body increases from ω_{i} = 2 rad/s to ω_{f} = 8 rad/s in t = 3 s, what is the angular acceleration α in rad/s^{2} ?$