A particle of mass m moves along a line y = d with constant velocity v. What is the angular momentum of the particle about the origin?

A. mvd — Angular momentum is defined as the cross product of position vector and linear momentum. Since the perpendicular distance from the origin to the line of motion is d, the magnitude is simply m v d.

JEE Advanced · PhysicsMedium

$A particle of mass m moves along a line y = d with constant velocity v parallel to the x-axis. What is the angular momentum of the particle about the origin?$

A. $m v d$
B. $\frac{m v d}{2}$
C. $0$
D. $2 m v d$

Show correct answer & step-by-step solution

Correct answer: A — $m v d$

Solution

The angular momentum is L = r \times p . The magnitude is L = p \cdot r_{⊥} = (m v) d .

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A particle of mass m moves along a line y=d with constant velocity v parallel to the x-axis. What is the angular momentum of the particle about the origin?

Solution

Attempt this question & track your score

More Rotational Motion practice questions

$A particle of mass m moves along a line y = d with constant velocity v parallel to the x-axis. What is the angular momentum of the particle about the origin?$