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A resistor of $10 \text{ } \Omega$ and an inductor of $0.1 \text{ H}$ are connected in series to a $50 \text{ V}$, $50 \text{ Hz}$ AC source. What is the phase angle between the voltage and the current?
- A.$\tan^{-1}(\pi)$
- B.$\tan^{-1}(0.5)$
- C.$45^\circ$
- D.$30^\circ$
Show correct answer & step-by-step solution
Correct answer: A — $\tan^{-1}(\pi)$
Solution
. Therefore, .
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